[分享]鸿蒙开发中，如何跳转手机系统浏览器，并打开指定链接？

下面的代码，用来打开任意APP，需要填充其包名和暴露的Entry名

static openApp(bundleName: string, abilityName: string) {
    let context = getContext() as common.UIAbilityContext
    let want: Want = {
      bundleName: bundleName,
      abilityName: abilityName,
    }
    context.startAbility(want)
}

startAbility可以带入Want参数，Want可以带入uri和行为

let want = {
action: 'ohos.want.action.viewData',
entities: ['entity.system.browsable'],
uri: 'https://www.baidu.com/'
};